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人気のある代数 >

solvefor x,f=x^2+kx+9

解

解く

x, f = x^{2} + k x + 9

解

x = \frac{- k + k ^{2} - 4 ( 9 - f )}{2}, x = \frac{- k - k ^{2} - 4 ( 9 - f )}{2}

解答ステップ

f = x^{2} + k x + 9

辺を交換する

x^{2} + k x + 9 = f

f

を左側に移動します

x^{2} + k x + 9 - f = 0

解くとthe二次式

x_{1, 2} = \frac{- k \pm k ^{2} - 4 \cdot 1 \cdot ( 9 - f )}{2 \cdot 1}

簡素化

k^{2} - 4 \cdot 1 \cdot (9 - f) : k^{2} - 4 (9 - f)

x_{1, 2} = \frac{- k \pm k ^{2} - 4 ( 9 - f )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- k + k ^{2} - 4 ( 9 - f )}{2 \cdot 1}, x_{2} = \frac{- k - k ^{2} - 4 ( 9 - f )}{2 \cdot 1}

x = \frac{- k + k ^{2} - 4 ( 9 - f )}{2 \cdot 1} : \frac{- k + k ^{2} - 4 ( 9 - f )}{2}

x = \frac{- k - k ^{2} - 4 ( 9 - f )}{2 \cdot 1} : \frac{- k - k ^{2} - 4 ( 9 - f )}{2}

二次equationの解:

x = \frac{- k + k ^{2} - 4 ( 9 - f )}{2}, x = \frac{- k - k ^{2} - 4 ( 9 - f )}{2}

グラフ

人気の例

3 y^{2} - 5 y - 6 = 0

solvefor x,4x^2+4y^2+12x+27=0

so l v e f or x, 4 x^{2} + 4 y^{2} + 12 x + 27 = 0

x^{2} + x - 20 = 1

solvefor y,z=(x^2+y^2)/(ln(x))

so l v e f or y, z = \frac{x ^{2} + y ^{2}}{ln ( x )}

18 x^{2} - 39 x - 15 = 0