z^2+11z+24=0

解

z^{2} + 11 z + 24 = 0

z = - 3, z = - 8

解答ステップ

z^{2} + 11 z + 24 = 0

解くとthe二次式

z_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot 24 = 5

z_{1, 2} = \frac{- 11 \pm 5}{2 \cdot 1}

解を分離する

z_{1} = \frac{- 11 + 5}{2 \cdot 1}, z_{2} = \frac{- 11 - 5}{2 \cdot 1}

z = \frac{- 11 + 5}{2 \cdot 1} : - 3

z = \frac{- 11 - 5}{2 \cdot 1} : - 8

二次equationの解:

z = - 3, z = - 8