z^2-9z+18=0

解

z^{2} - 9 z + 18 = 0

z = 6, z = 3

解答ステップ

z^{2} - 9 z + 18 = 0

解くとthe二次式

z_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 18 = 3

z_{1, 2} = \frac{- ( - 9 ) \pm 3}{2 \cdot 1}

解を分離する

z_{1} = \frac{- ( - 9 ) + 3}{2 \cdot 1}, z_{2} = \frac{- ( - 9 ) - 3}{2 \cdot 1}

z = \frac{- ( - 9 ) + 3}{2 \cdot 1} : 6

z = \frac{- ( - 9 ) - 3}{2 \cdot 1} : 3

二次equationの解:

z = 6, z = 3