6t^2-42t+72=0

解

6 t^{2} - 42 t + 72 = 0

t = 4, t = 3

解答ステップ

6 t^{2} - 42 t + 72 = 0

解くとthe二次式

t_{1, 2} = \frac{- ( - 42 ) \pm ( - 42 ) ^{2} - 4 \cdot 6 \cdot 72}{2 \cdot 6}

(- 42)^{2} - 4 \cdot 6 \cdot 72 = 6

t_{1, 2} = \frac{- ( - 42 ) \pm 6}{2 \cdot 6}

解を分離する

t_{1} = \frac{- ( - 42 ) + 6}{2 \cdot 6}, t_{2} = \frac{- ( - 42 ) - 6}{2 \cdot 6}

t = \frac{- ( - 42 ) + 6}{2 \cdot 6} : 4

t = \frac{- ( - 42 ) - 6}{2 \cdot 6} : 3

二次equationの解:

t = 4, t = 3