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受欢迎的代数 >

((x-3)^2)/2-x+x^2=x-(x-2)

解答

\frac{( x - 3 ) ^{2}}{2} - x + x^{2} = x - (x - 2)

解答

x = \frac{5}{3}, x = 1

+1

十进制

x = 1.66666 \dots, x = 1

求解步骤

\frac{( x - 3 ) ^{2}}{2} - x + x^{2} = x - (x - 2)

在两边乘以

2

(x - 3)^{2} - 2 x + 2 x^{2} = 2 x - 2 (x - 2)

展开

(x - 3)^{2} - 2 x + 2 x^{2} : 3 x^{2} - 8 x + 9

展开

2 x - 2 (x - 2) : 4

3 x^{2} - 8 x + 9 = 4

将

4

para o lado esquerdo

3 x^{2} - 8 x + 5 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 3 \cdot 5}{2 \cdot 3}

(- 8)^{2} - 4 \cdot 3 \cdot 5 = 2

x_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 3}

将解分隔开

x_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 3}

x = \frac{- ( - 8 ) + 2}{2 \cdot 3} : \frac{5}{3}

x = \frac{- ( - 8 ) - 2}{2 \cdot 3} : 1

二次方程组的解是:

x = \frac{5}{3}, x = 1

作图

流行的例子

3 c + 10 = 28

3q-2<=-10\lor 3q-2>10

3 q - 2 \leq - 10 or 3 q - 2 > 10

因式分解 4u^2v+16uv^2+16v^3

f a c t or 4 u^{2} v + 16 u v^{2} + 16 v^{3}

化简 (6^5)/(6^2)

s im pl i f y \frac{6 ^{5}}{6 ^{2}}

因式分解 x^2-18x+80

f a c t or x^{2} - 18 x + 80