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受欢迎的代数 >

3=(1-2(1)+5)t^2+(2(1)-2(1))t+1

解答

3 = (1 - 2 (1) + 5) t^{2} + (2 (1) - 2 (1)) t + 1

解答

t = \frac{1}{2}, t = - \frac{1}{2}

+1

十进制

t = 0.70710 \dots, t = - 0.70710 \dots

求解步骤

3 = (1 - 2 (1) + 5) t^{2} + (2 (1) - 2 (1)) t + 1

展开

(1 - 2 (1) + 5) t^{2} + (2 (1) - 2 (1)) t + 1 : 4 t^{2} + 1

3 = 4 t^{2} + 1

交换两边

4 t^{2} + 1 = 3

将

3

para o lado esquerdo

4 t^{2} - 2 = 0

使用求根公式求解

t_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 4 ( - 2 )}{2 \cdot 4}

0^{2} - 4 \cdot 4 (- 2) = 42

t_{1, 2} = \frac{- 0 \pm 4 2}{2 \cdot 4}

将解分隔开

t_{1} = \frac{- 0 + 4 2}{2 \cdot 4}, t_{2} = \frac{- 0 - 4 2}{2 \cdot 4}

t = \frac{- 0 + 4 2}{2 \cdot 4} : \frac{1}{2}

t = \frac{- 0 - 4 2}{2 \cdot 4} : - \frac{1}{2}

二次方程组的解是:

t = \frac{1}{2}, t = - \frac{1}{2}

作图

流行的例子

x^{2} + 4^{2} = 7^{2}

(x-4)^2+(x-7)^2=15

(x - 4)^{2} + (x - 7)^{2} = 15

solvefor y,y^2(2-x)=x^3

so l v e f or y, y^{2} (2 - x) = x^{3}

4 x^{2} + 44 x + 121 = 0

16 x^{2} + 25 x + 9 = 0