x^2+sqrt(2)x+1=0

解

x^{2} + 2 x + 1 = 0

x = - \frac{2}{2} + i \frac{2}{2}, x = - \frac{2}{2} - i \frac{2}{2}

解答ステップ

x^{2} + 2 x + 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- 2 \pm ( 2 ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

簡素化

(2)^{2} - 4 \cdot 1 \cdot 1 : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

x = \frac{- 2 + 2 i}{2 \cdot 1} : - \frac{2}{2} + i \frac{2}{2}

x = \frac{- 2 - 2 i}{2 \cdot 1} : - \frac{2}{2} - i \frac{2}{2}

二次equationの解:

x = - \frac{2}{2} + i \frac{2}{2}, x = - \frac{2}{2} - i \frac{2}{2}