mx^2+(2m-1)x+m-1=0

解

m x^{2} + (2 m - 1) x + m - 1 = 0

x = \frac{- m + 1}{m}, x = - 1; m \neq = 0

解答ステップ

m x^{2} + (2 m - 1) x + m - 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 2 m - 1 ) \pm ( 2 m - 1 ) ^{2} - 4 m ( m - 1 )}{2 m}

(2 m - 1)^{2} - 4 m (m - 1) = 1

x_{1, 2} = \frac{- ( 2 m - 1 ) \pm 1}{2 m}; m \neq = 0

解を分離する

x_{1} = \frac{- ( 2 m - 1 ) + 1}{2 m}, x_{2} = \frac{- ( 2 m - 1 ) - 1}{2 m}

x = \frac{- ( 2 m - 1 ) + 1}{2 m} : \frac{- m + 1}{m}

x = \frac{- ( 2 m - 1 ) - 1}{2 m} : - 1

二次equationの解:

x = \frac{- m + 1}{m}, x = - 1; m \neq = 0