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受欢迎的代数 >

-y^2+2=12y-7

解答

- y^{2} + 2 = 12 y - 7

解答

y = - 3 (2 + 5), y = 3 (5 - 2)

+1

十进制

y = - 12.70820 \dots, y = 0.70820 \dots

求解步骤

- y^{2} + 2 = 12 y - 7

将

7

para o lado esquerdo

- y^{2} + 9 = 12 y

将

12 y

para o lado esquerdo

- y^{2} + 9 - 12 y = 0

改写成标准形式

a x^{2} + b x + c = 0

- y^{2} - 12 y + 9 = 0

使用求根公式求解

y_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 ( - 1 ) \cdot 9}{2 ( - 1 )}

(- 12)^{2} - 4 (- 1) \cdot 9 = 65

y_{1, 2} = \frac{- ( - 12 ) \pm 6 5}{2 ( - 1 )}

将解分隔开

y_{1} = \frac{- ( - 12 ) + 6 5}{2 ( - 1 )}, y_{2} = \frac{- ( - 12 ) - 6 5}{2 ( - 1 )}

y = \frac{- ( - 12 ) + 6 5}{2 ( - 1 )} : - 3 (2 + 5)

y = \frac{- ( - 12 ) - 6 5}{2 ( - 1 )} : 3 (5 - 2)

二次方程组的解是:

y = - 3 (2 + 5), y = 3 (5 - 2)

作图

流行的例子

9 x^{2} + 6 x + 1 = 4

(y - 6)^{2} + 10 = 3 y

y^{2} = 10

7(x-4)2-3(x+5)2=4(x+1)(x-1)-2

7 (x - 4) 2 - 3 (x + 5) 2 = 4 (x + 1) (x - 1) - 2

- x^{2} - x - 6 = 0