What is (2x)/3-((x-1))/4 <((x-1))/8 ?

The solution to (2x)/3-((x-1))/4 <((x-1))/8 is x<-9/7

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(2x)/3-((x-1))/4 <((x-1))/8

\frac{2 x}{3} - \frac{( x - 1 )}{4} < \frac{( x - 1 )}{8}

x < - \frac{9}{7}

Interval Notation

(- \infty, - \frac{9}{7})

Decimal Notation

x < - 1.28571 \dots

Solution steps

\frac{2 x}{3} - \frac{( x - 1 )}{4} < \frac{( x - 1 )}{8}

\frac{2 x}{3} - \frac{x - 1}{4} < \frac{( x - 1 )}{8}

Multiply by LCM

16 x - 6 (x - 1) < 3 (x - 1)

Expand

- 6 (x - 1) : - 6 x + 6

16 x - 6 x + 6 < 3 (x - 1)

Add similar elements:

16 x - 6 x = 10 x

10 x + 6 < 3 (x - 1)

Expand

3 (x - 1) : 3 x - 3

10 x + 6 < 3 x - 3

Move

6

to the right side

10 x < 3 x - 9

Move

3 x

to the left side

7 x < - 9

Divide both sides by

7

x < - \frac{9}{7}

2 b^{3} + 6 b

x + 0.02 x = 255

4 (- 5) (- 2) (- 9)

- 32 n^{9} + 32 n^{6} + 40 n^{5}

\frac{375}{2} \cdot 3.3

What is (2x)/3-((x-1))/4 <((x-1))/8 ?
The solution to (2x)/3-((x-1))/4 <((x-1))/8 is x<-9/7