What are the solutions to the equation x^2-9x+9=0 ?

The solutions to the equation x^2-9x+9=0 are x=(9+3sqrt(5))/2 ,x=(9-3sqrt(5))/2

Find the zeros of x^2-9x+9=0

The zeros of x^2-9x+9=0 are x=(9+3sqrt(5))/2 ,x=(9-3sqrt(5))/2

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x^{2} - 9 x + 9 = 0

x = \frac{9 + 3 5}{2}, x = \frac{9 - 3 5}{2}

Decimal Notation

x = 7.85410 \dots, x = 1.14589 \dots

Solution steps

x^{2} - 9 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 9 = 35

x_{1, 2} = \frac{- ( - 9 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 5}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 3 5}{2 \cdot 1}

x = \frac{- ( - 9 ) + 3 5}{2 \cdot 1} : \frac{9 + 3 5}{2}

x = \frac{- ( - 9 ) - 3 5}{2 \cdot 1} : \frac{9 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{9 + 3 5}{2}, x = \frac{9 - 3 5}{2}

32 \cdot 5

2 (x - 1)^{2} - 5 = 3

4 x^{2} - (2 x + 3)^{2}

(\frac{5 ^{3}}{5 ^{4}})^{- 3}

x^{2} - 9 = (x + 3) (x - 3)

What are the solutions to the equation x^2-9x+9=0 ?
The solutions to the equation x^2-9x+9=0 are x=(9+3sqrt(5))/2 ,x=(9-3sqrt(5))/2
Find the zeros of x^2-9x+9=0
The zeros of x^2-9x+9=0 are x=(9+3sqrt(5))/2 ,x=(9-3sqrt(5))/2