What is 0>= (5-x)/2 >=-10 ?

The solution to 0>= (5-x)/2 >=-10 is 5<= x<= 25

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0>= (5-x)/2 >=-10

0 \geq \frac{5 - x}{2} \geq - 10

5 \leq x \leq 25

Interval Notation

[5, 25]

Solution steps

0 \geq \frac{5 - x}{2} \geq - 10

a \geq u \geq b

then

a \geq u and u \geq b

0 \geq \frac{5 - x}{2} and \frac{5 - x}{2} \geq - 10

0 \geq \frac{5 - x}{2} : x \geq 5

\frac{5 - x}{2} \geq - 10 : x \leq 25

Combine the intervals

x \geq 5 and x \leq 25

Merge Overlapping Intervals

5 \leq x \leq 25

\frac{( n + 2 ) !}{( n + 1 ) !}

(- 1)^{\frac{4}{5}}

32 e^{2} - 50

36 x^{2} - y^{6}

5 \cdot 32