-9/(2x^{3/2)}

Lösung

- \frac{9}{2 x ^{\frac{3}{2}}}

- \frac{9}{2 x x ^{\frac{1}{2}}}

Schritte zur Lösung

- \frac{9}{2 x ^{\frac{3}{2}}}

Wende Exponentenregel an:

a^{b + c} = a^{b} \cdot a^{c}

x^{\frac{3}{2}} = x^{1 + \frac{1}{2}} = x x^{\frac{1}{2}}

= - \frac{9}{2 x x ^{\frac{1}{2}}}

f a c t or m^{2} - 18 m - 19

x^{2} - 2 x - 2 \geq 1

5 x^{2} + 3 x - 5 = 0

(x + 2) (x + 2) = 0

f a c t or 5 b^{2} + 21 b + 4