展開する (8xy^3+1)*(18sin^8(t)cos(t))

解

展開する

(8 x y^{3} + 1) \cdot (18 sin^{8} (t) cos (t))

144 x sin^{8} (t) y^{3} cos (t) + 18 sin^{8} (t) cos (t)

解答ステップ

(8 x y^{3} + 1) (18 sin^{8} (t) cos (t))

= (18 sin^{8} (t) cos (t)) (8 x y^{3} + 1)

分配法則を適用する:

a (b + c) = ab + a c

(18 sin^{8} (t) cos (t)) (8 x y^{3} + 1) = 18 sin^{8} (t) cos (t) \cdot 8 x y^{3} + 18 sin^{8} (t) cos (t) \cdot 1

= 18 sin^{8} (t) cos (t) \cdot 8 x y^{3} + 18 sin^{8} (t) cos (t) \cdot 1

簡素化

18 sin^{8} (t) cos (t) \cdot 8 x y^{3} + 18 sin^{8} (t) cos (t) \cdot 1 : 144 x sin^{8} (t) y^{3} cos (t) + 18 sin^{8} (t) cos (t)

= 144 x sin^{8} (t) y^{3} cos (t) + 18 sin^{8} (t) cos (t)