展開する (4,-1,2)left(-6/7 ,-2/7 , 11/7)

解

展開する

(4, - 1, 2) l e f t (- \frac{6}{7}, - \frac{2}{7}, \frac{11}{7})

- 4 e l f t, \frac{6}{7}, - 4 e l f t, \frac{2}{7}, \frac{11}{7} + 1 e l f t, 2 \cdot \frac{6}{7}, 1, 2 \cdot \frac{2}{7}, \frac{11}{7}

解答ステップ

(4, - 1, 2) l e f t (- \frac{6}{7}, - \frac{2}{7}, \frac{11}{7})

= e (4, - 1 \cdot 2,) (- \frac{6}{7}, - \frac{2}{7} \cdot \frac{11}{7},) l f t

拡張

(4, - 1, 2) (- \frac{6}{7}, - \frac{2}{7}, \frac{11}{7}) : - 4, \frac{6}{7}, - 4, \frac{2}{7}, \frac{11}{7} + 1, 2 \cdot \frac{6}{7}, 1, 2 \cdot \frac{2}{7}, \frac{11}{7}

= l e f t (- 4, \frac{6}{7}, - 4, \frac{2}{7}, \frac{11}{7} + 1, 2 \cdot \frac{6}{7}, 1, 2 \cdot \frac{2}{7}, \frac{11}{7})

拡張

l e f t (- 4, \frac{6}{7}, - 4, \frac{2}{7}, \frac{11}{7} + 1, 2 \cdot \frac{6}{7}, 1, 2 \cdot \frac{2}{7}, \frac{11}{7}) : - 4 e l f t, \frac{6}{7}, - 4 e l f t, \frac{2}{7}, \frac{11}{7} + 1 e l f t, 2 \cdot \frac{6}{7}, 1, 2 \cdot \frac{2}{7}, \frac{11}{7}

= - 4 e l f t, \frac{6}{7}, - 4 e l f t, \frac{2}{7}, \frac{11}{7} + 1 e l f t, 2 \cdot \frac{6}{7}, 1, 2 \cdot \frac{2}{7}, \frac{11}{7}