erweitern (L^2x^2-3Lx^3+2x^4)/(L^3)

Lösung

erweitern

\frac{L ^{2} x ^{2} - 3 L x ^{3} + 2 x ^{4}}{L ^{3}}

\frac{x ^{2}}{L} - \frac{3 x ^{3}}{L ^{2}} + \frac{2 x ^{4}}{L ^{3}}

Schritte zur Lösung

\frac{L ^{2} x ^{2} - 3 L x ^{3} + 2 x ^{4}}{L ^{3}}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{L ^{2} x ^{2} - 3 L x ^{3} + 2 x ^{4}}{L ^{3}} = \frac{L ^{2} x ^{2}}{L ^{3}} - \frac{3 L x ^{3}}{L ^{3}} + \frac{2 x ^{4}}{L ^{3}}

= \frac{L ^{2} x ^{2}}{L ^{3}} - \frac{3 L x ^{3}}{L ^{3}} + \frac{2 x ^{4}}{L ^{3}}

Streiche

\frac{L ^{2} x ^{2}}{L ^{3}} : \frac{x ^{2}}{L}

= \frac{x ^{2}}{L} - \frac{3 L x ^{3}}{L ^{3}} + \frac{2 x ^{4}}{L ^{3}}

Streiche

\frac{3 L x ^{3}}{L ^{3}} : \frac{3 x ^{3}}{L ^{2}}

= \frac{x ^{2}}{L} - \frac{3 x ^{3}}{L ^{2}} + \frac{2 x ^{4}}{L ^{3}}

e x p an d \frac{( a - b ) ^{2}}{( a + b )}

e x p an d lo g_{9} (7 \frac{s ^{6} t}{81})

e x p an d \frac{2}{9 + 4 x}

s im pl i f y (x^{3} - 2) (sec^{2} (x))

s im pl i f y e^{in (s e c (θ) + t a n (θ))}