展开 (ln|tan(x)+sec(x)|-sin(x))sin(x)

解答

展开

(ln ∣ tan (x) + sec (x) ∣ - sin (x)) sin (x)

sin (x) ln ∣ tan (x) + sec (x) ∣ - sin^{2} (x)

求解步骤

(ln ∣ tan (x) + sec (x) ∣ - sin (x)) sin (x)

= sin (x) (ln ∣ tan (x) + sec (x) ∣ - sin (x))

使用分配律:

a (b - c) = ab - a c

a = sin (x), b = ln ∣ tan (x) + sec (x) ∣, c = sin (x)

= sin (x) ln ∣ tan (x) + sec (x) ∣ - sin (x) sin (x)

sin (x) sin (x) = sin^{2} (x)

= sin (x) ln ∣ tan (x) + sec (x) ∣ - sin^{2} (x)

e x p an d \frac{3 ( x - 4 )}{x}

s im pl i f y (1 - x - x^{2}) (\frac{2 x}{3} + 5)

e x p an d \frac{4 x ^{2} - 9 x + 2}{( x + 3 ) ( x ^{2} + 4 )}

e x p an d 8 w (a x -, + cz) - 8 (a x -, + cz)

e x p an d \frac{( ( a + b ) ^{2} - c ^{2} )}{( ( a - b ) ^{2} - c ^{2} )}