What is factor 8x^2y^2+20xy^2-28x^3y^4 ?

The solution to factor 8x^2y^2+20xy^2-28x^3y^4 is 4xy^2(2x+5-7x^2y^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 8x^2y^2+20xy^2-28x^3y^4

factor

8 x^{2} y^{2} + 20 x y^{2} - 28 x^{3} y^{4}

4 x y^{2} (2 x + 5 - 7 x^{2} y^{2})

Solution steps

8 x^{2} y^{2} + 20 x y^{2} - 28 x^{3} y^{4}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

x^{2} y^{2} = xx y^{2}, x^{3} y^{4} = x x^{2} y^{2} y^{2}

= 8 xx y^{2} + 20 x y^{2} - 28 x x^{2} y^{2} y^{2}

Rewrite

- 28

7 \cdot 4

Rewrite

20

5 \cdot 4

= 2 \cdot 4 xx y^{2} + 5 \cdot 4 x y^{2} + 7 \cdot 4 x x^{2} y^{2} y^{2}

Factor out common term

4 x y^{2}

= 4 x y^{2} (2 x + 5 - 7 x^{2} y^{2})

x^{4} - a^{4}

13!

2 b^{2} + 29 b + 90

4 x^{2} - x - 3 = - 3

x (x - 3) \leq 28

What is factor 8x^2y^2+20xy^2-28x^3y^4 ?
The solution to factor 8x^2y^2+20xy^2-28x^3y^4 is 4xy^2(2x+5-7x^2y^2)