What are the solutions to the equation 49x^2+28x=-3 ?

The solutions to the equation 49x^2+28x=-3 are x=-1/7 ,x=-3/7

Find the zeros of 49x^2+28x=-3

The zeros of 49x^2+28x=-3 are x=-1/7 ,x=-3/7

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49 x^{2} + 28 x = - 3

x = - \frac{1}{7}, x = - \frac{3}{7}

Decimal Notation

x = - 0.14285 \dots, x = - 0.42857 \dots

Solution steps

49 x^{2} + 28 x = - 3

Move

3

to the left side

49 x^{2} + 28 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 49 \cdot 3}{2 \cdot 49}

2 8^{2} - 4 \cdot 49 \cdot 3 = 14

x_{1, 2} = \frac{- 28 \pm 14}{2 \cdot 49}

Separate the solutions

x_{1} = \frac{- 28 + 14}{2 \cdot 49}, x_{2} = \frac{- 28 - 14}{2 \cdot 49}

x = \frac{- 28 + 14}{2 \cdot 49} : - \frac{1}{7}

x = \frac{- 28 - 14}{2 \cdot 49} : - \frac{3}{7}

The solutions to the quadratic equation are:

x = - \frac{1}{7}, x = - \frac{3}{7}

∣ 2 a + 9 ∣ = ∣ 3 a - 3 ∣

10 x - 100

4 x - (68 - x) \cdot 6 = 22

\frac{5 ! 7 !}{3 ! 6 !}

(x + 1)^{2} = 4

What are the solutions to the equation 49x^2+28x=-3 ?
The solutions to the equation 49x^2+28x=-3 are x=-1/7 ,x=-3/7
Find the zeros of 49x^2+28x=-3
The zeros of 49x^2+28x=-3 are x=-1/7 ,x=-3/7