What are the solutions to the equation 0=x^2+9x+18 ?

The solutions to the equation 0=x^2+9x+18 are x=-3,x=-6

Find the zeros of 0=x^2+9x+18

The zeros of 0=x^2+9x+18 are x=-3,x=-6

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0 = x^{2} + 9 x + 18

x = - 3, x = - 6

Solution steps

0 = x^{2} + 9 x + 18

Switch sides

x^{2} + 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

x_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 3}{2 \cdot 1}, x_{2} = \frac{- 9 - 3}{2 \cdot 1}

x = \frac{- 9 + 3}{2 \cdot 1} : - 3

x = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = - 3, x = - 6

8 = \frac{k}{- 3} - 2

4 y \leq 5 y - 8

(2 m - 1)^{2} = 49

9 m - 18 n

∣ x - 12 ∣ \leq 15

What are the solutions to the equation 0=x^2+9x+18 ?
The solutions to the equation 0=x^2+9x+18 are x=-3,x=-6
Find the zeros of 0=x^2+9x+18
The zeros of 0=x^2+9x+18 are x=-3,x=-6