What are the solutions to the equation (-4/5)^2+y^2=1 ?

The solutions to the equation (-4/5)^2+y^2=1 are y= 3/5 ,y=-3/5

Find the zeros of (-4/5)^2+y^2=1

The zeros of (-4/5)^2+y^2=1 are y= 3/5 ,y=-3/5

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(- \frac{4}{5})^{2} + y^{2} = 1

y = \frac{3}{5}, y = - \frac{3}{5}

Decimal Notation

y = 0.6, y = - 0.6

Solution steps

(- \frac{4}{5})^{2} + y^{2} = 1

Expand

(- \frac{4}{5})^{2} + y^{2} : \frac{16}{25} + y^{2}

\frac{16}{25} + y^{2} = 1

Move

\frac{16}{25}

to the right side

y^{2} = 1 - \frac{16}{25}

Simplify

1 - \frac{16}{25} : \frac{9}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{9}{25}, y = - \frac{9}{25}

\frac{9}{25} = \frac{3}{5}

- \frac{9}{25} = - \frac{3}{5}

y = \frac{3}{5}, y = - \frac{3}{5}

- x^{3} + 4 x^{2} + 15 x - 18

x^{2} + 3 - x = 16

4 x - 2 x^{2}

∣ n ∣ = 12

\frac{x}{3} - \frac{3}{4} = \frac{3 x + 12}{12}

What are the solutions to the equation (-4/5)^2+y^2=1 ?
The solutions to the equation (-4/5)^2+y^2=1 are y= 3/5 ,y=-3/5
Find the zeros of (-4/5)^2+y^2=1
The zeros of (-4/5)^2+y^2=1 are y= 3/5 ,y=-3/5