展开 (tan(t))/((t-3)(t-5))

解答

展开

\frac{tan ( t )}{( t - 3 ) ( t - 5 )}

\frac{tan ( t )}{t ^{2} - 8 t + 15}

求解步骤

\frac{tan ( t )}{( t - 3 ) ( t - 5 )}

乘开

(t - 3) (t - 5) : t^{2} - 8 t + 15

= \frac{tan ( t )}{t ^{2} - 8 t + 15}

s im pl i f y (x - 2) (x + \frac{3}{4})

s im pl i f y (3 x - 4) (2 x - 1)

e x p an d e^{x} (\frac{d y}{d x} + y)

e x p an d \frac{( x ^{2} - 4 ) ( x - 3 )}{x + 1}

e x p an d (5 + 3) (6 - 4)