展开 (8640e^{-0.96t})/((1+3e^{-0.96t))^2}

解答

展开

\frac{8640 e ^{- 0.96 t}}{( 1 + 3 e ^{- 0.96 t} ) ^{2}}

\frac{8640 e ^{- 0.96 t}}{1 + 6 e ^{- 0.96 t} + 9 e ^{- 1.92 t}}

求解步骤

\frac{8640 e ^{- 0.96 t}}{( 1 + 3 e ^{- 0.96 t} ) ^{2}}

(1 + 3 e^{- 0.96 t})^{2} = 1 + 6 e^{- 0.96 t} + 9 e^{- 1.92 t}

= \frac{8640 e ^{- 0.96 t}}{1 + 6 e ^{- 0.96 t} + 9 e ^{- 1.92 t}}

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