erweitern (x^{1/2}-2y^{1/2})^2

Lösung

erweitern

(x^{\frac{1}{2}} - 2 y^{\frac{1}{2}})^{2}

x - 4 x^{\frac{1}{2}} y^{\frac{1}{2}} + 4 y

Schritte zur Lösung

(x^{\frac{1}{2}} - 2 y^{\frac{1}{2}})^{2}

Wende Formel für perfekte quadratische Gleichungen an:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(x^{\frac{1}{2}} - 2 y^{\frac{1}{2}})^{2} = (x^{\frac{1}{2}})^{2} - 2 x^{\frac{1}{2}} \cdot 2 y^{\frac{1}{2}} + (2 y^{\frac{1}{2}})^{2}

= (x^{\frac{1}{2}})^{2} - 2 x^{\frac{1}{2}} \cdot 2 y^{\frac{1}{2}} + (2 y^{\frac{1}{2}})^{2}

(x^{\frac{1}{2}})^{2} = x

2 x^{\frac{1}{2}} \cdot 2 y^{\frac{1}{2}} = 4 x^{\frac{1}{2}} y^{\frac{1}{2}}

(2 y^{\frac{1}{2}})^{2} = 4 y

= x - 4 x^{\frac{1}{2}} y^{\frac{1}{2}} + 4 y

e x p an d - (e^{- t} - e^{- t} t) (e^{t})

e x p an d \frac{( x - 2 ) ( x - 3 )}{x ^{2} - 36}

s im pl i f y (x - 3 + x + 2)^{2}

e x p an d \frac{6 x + 2}{( x + 1 ) ( 2 x + 1 )}

e x p an d \frac{5}{( s - 2 ) ( s - 3 ) ( s - 6 )}