faktorisieren 2x^3-4x^2-14x+28

Lösung

faktorisieren

2 x^{3} - 4 x^{2} - 14 x + 28

2 (x - 2) (x^{2} - 7)

Schritte zur Lösung

2 x^{3} - 4 x^{2} - 14 x + 28

Klammere gleiche Terme aus

2 : 2 (x^{3} - 2 x^{2} - 7 x + 14)

= 2 (x^{3} - 2 x^{2} - 7 x + 14)

Faktorisiere

x^{3} - 2 x^{2} - 7 x + 14 : (x - 2) (x^{2} - 7)

= 2 (x - 2) (x^{2} - 7)

2 f - 9 = 14 f + 1

f a c t or 2 x - 2

\frac{3}{4} x^{2} + \frac{4}{5} x = 0

4 b - 10 = 2 b + 8

4 - x^{2} = x + 2