What are the solutions to the equation x^2-5x-5=0 ?

The solutions to the equation x^2-5x-5=0 are x=(5+3sqrt(5))/2 ,x=(5-3sqrt(5))/2

Find the zeros of x^2-5x-5=0

The zeros of x^2-5x-5=0 are x=(5+3sqrt(5))/2 ,x=(5-3sqrt(5))/2

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x^{2} - 5 x - 5 = 0

x = \frac{5 + 3 5}{2}, x = \frac{5 - 3 5}{2}

Decimal Notation

x = 5.85410 \dots, x = - 0.85410 \dots

Solution steps

x^{2} - 5 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 5) = 35

x_{1, 2} = \frac{- ( - 5 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3 5}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3 5}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3 5}{2 \cdot 1} : \frac{5 + 3 5}{2}

x = \frac{- ( - 5 ) - 3 5}{2 \cdot 1} : \frac{5 - 3 5}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 3 5}{2}, x = \frac{5 - 3 5}{2}

4^{2} + 2^{2}

11 x^{3} + 125 x^{2} + 45 x + 11

4 x^{3} - x

\frac{4}{5 - 2 i}

- 3 (2 a - 3) + 2 = 3 (a + 7)

What are the solutions to the equation x^2-5x-5=0 ?
The solutions to the equation x^2-5x-5=0 are x=(5+3sqrt(5))/2 ,x=(5-3sqrt(5))/2
Find the zeros of x^2-5x-5=0
The zeros of x^2-5x-5=0 are x=(5+3sqrt(5))/2 ,x=(5-3sqrt(5))/2