What are the solutions to the equation 4x^2+28x=-45 ?

The solutions to the equation 4x^2+28x=-45 are x=-5/2 ,x=-9/2

Find the zeros of 4x^2+28x=-45

The zeros of 4x^2+28x=-45 are x=-5/2 ,x=-9/2

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4 x^{2} + 28 x = - 45

x = - \frac{5}{2}, x = - \frac{9}{2}

Decimal Notation

x = - 2.5, x = - 4.5

Solution steps

4 x^{2} + 28 x = - 45

Move

45

to the left side

4 x^{2} + 28 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 4 \cdot 45}{2 \cdot 4}

2 8^{2} - 4 \cdot 4 \cdot 45 = 8

x_{1, 2} = \frac{- 28 \pm 8}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 28 + 8}{2 \cdot 4}, x_{2} = \frac{- 28 - 8}{2 \cdot 4}

x = \frac{- 28 + 8}{2 \cdot 4} : - \frac{5}{2}

x = \frac{- 28 - 8}{2 \cdot 4} : - \frac{9}{2}

The solutions to the quadratic equation are:

x = - \frac{5}{2}, x = - \frac{9}{2}

10 = 4 (\frac{3 + b}{2})

3 x^{3} - 4 x^{2} - 7 x - 2

\frac{- 12 + - 45}{24}

\frac{1042 - 214}{5}

520 + 24 - 180 + 754

What are the solutions to the equation 4x^2+28x=-45 ?
The solutions to the equation 4x^2+28x=-45 are x=-5/2 ,x=-9/2
Find the zeros of 4x^2+28x=-45
The zeros of 4x^2+28x=-45 are x=-5/2 ,x=-9/2