What are the solutions to the equation x^2-7x=6x ?

The solutions to the equation x^2-7x=6x are x=13,x=0

Find the zeros of x^2-7x=6x

The zeros of x^2-7x=6x are x=13,x=0

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x^{2} - 7 x = 6 x

x = 13, x = 0

Solution steps

x^{2} - 7 x = 6 x

Move

6 x

to the left side

x^{2} - 13 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot 0 = 13

x_{1, 2} = \frac{- ( - 13 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 13 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 13 ) - 13}{2 \cdot 1}

x = \frac{- ( - 13 ) + 13}{2 \cdot 1} : 13

x = \frac{- ( - 13 ) - 13}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 13, x = 0

\frac{2 + 6 i}{1 + i}

2 x^{2} - 2 x - 3 = 0

(- 5)^{1}

\frac{4 a ^{5}}{7 b ^{4}} \cdot \frac{2 b ^{2}}{2 a ^{4}}

m^{2} + 2 m - 35

What are the solutions to the equation x^2-7x=6x ?
The solutions to the equation x^2-7x=6x are x=13,x=0
Find the zeros of x^2-7x=6x
The zeros of x^2-7x=6x are x=13,x=0