What are the solutions to the equation 4x^2+40x-140=700 ?

The solutions to the equation 4x^2+40x-140=700 are x=-5+sqrt(235),x=-5-sqrt(235)

Find the zeros of 4x^2+40x-140=700

The zeros of 4x^2+40x-140=700 are x=-5+sqrt(235),x=-5-sqrt(235)

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4 x^{2} + 40 x - 140 = 700

x = - 5 + 235, x = - 5 - 235

Decimal Notation

x = 10.32970 \dots, x = - 20.32970 \dots

Solution steps

4 x^{2} + 40 x - 140 = 700

Move

700

to the left side

4 x^{2} + 40 x - 840 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 \cdot 4 ( - 840 )}{2 \cdot 4}

4 0^{2} - 4 \cdot 4 (- 840) = 8235

x_{1, 2} = \frac{- 40 \pm 8 235}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 40 + 8 235}{2 \cdot 4}, x_{2} = \frac{- 40 - 8 235}{2 \cdot 4}

x = \frac{- 40 + 8 235}{2 \cdot 4} : - 5 + 235

x = \frac{- 40 - 8 235}{2 \cdot 4} : - 5 - 235

The solutions to the quadratic equation are:

x = - 5 + 235, x = - 5 - 235

x^{2} + 6 x - 55 = 0

(6 x - 5 y) (6 x + 5 y)

\frac{v + 9}{3} = 8

∣ 6 w + 2 ∣ - 6 > 8

- 4.2 y + 2.1 > - 2.52

What are the solutions to the equation 4x^2+40x-140=700 ?
The solutions to the equation 4x^2+40x-140=700 are x=-5+sqrt(235),x=-5-sqrt(235)
Find the zeros of 4x^2+40x-140=700
The zeros of 4x^2+40x-140=700 are x=-5+sqrt(235),x=-5-sqrt(235)