What are the solutions to the equation 2x^2+7x-17=0 ?

The solutions to the equation 2x^2+7x-17=0 are x=(-7+sqrt(185))/4 ,x=(-7-sqrt(185))/4

Find the zeros of 2x^2+7x-17=0

The zeros of 2x^2+7x-17=0 are x=(-7+sqrt(185))/4 ,x=(-7-sqrt(185))/4

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2 x^{2} + 7 x - 17 = 0

x = \frac{- 7 + 185}{4}, x = \frac{- 7 - 185}{4}

Decimal Notation

x = 1.65036 \dots, x = - 5.15036 \dots

Solution steps

2 x^{2} + 7 x - 17 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 2 ( - 17 )}{2 \cdot 2}

7^{2} - 4 \cdot 2 (- 17) = 185

x_{1, 2} = \frac{- 7 \pm 185}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 7 + 185}{2 \cdot 2}, x_{2} = \frac{- 7 - 185}{2 \cdot 2}

x = \frac{- 7 + 185}{2 \cdot 2} : \frac{- 7 + 185}{4}

x = \frac{- 7 - 185}{2 \cdot 2} : \frac{- 7 - 185}{4}

The solutions to the quadratic equation are:

x = \frac{- 7 + 185}{4}, x = \frac{- 7 - 185}{4}

(\frac{12682.3}{9521})^{\frac{1}{4}} - 1

x + 5 x \leq 0

- 10 g - (1 - 4 g) - 2 \geq 5

- 15 x \leq - 6

0 = 16 t^{2} + 324

What are the solutions to the equation 2x^2+7x-17=0 ?
The solutions to the equation 2x^2+7x-17=0 are x=(-7+sqrt(185))/4 ,x=(-7-sqrt(185))/4
Find the zeros of 2x^2+7x-17=0
The zeros of 2x^2+7x-17=0 are x=(-7+sqrt(185))/4 ,x=(-7-sqrt(185))/4