What are the solutions to the equation 3x(2x+3)=2x(x+4.5)+2 ?

The solutions to the equation 3x(2x+3)=2x(x+4.5)+2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

Find the zeros of 3x(2x+3)=2x(x+4.5)+2

The zeros of 3x(2x+3)=2x(x+4.5)+2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))

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3 x (2 x + 3) = 2 x (x + 4.5) + 2

x = \frac{1}{2}, x = - \frac{1}{2}

Decimal Notation

x = 0.70710 \dots, x = - 0.70710 \dots

Solution steps

3 x (2 x + 3) = 2 x (x + 4.5) + 2

Expand

3 x (2 x + 3) : 6 x^{2} + 9 x

Expand

2 x (x + 4.5) + 2 : 2 x^{2} + 9 x + 2

6 x^{2} + 9 x = 2 x^{2} + 9 x + 2

Move

9 x

to the left side

6 x^{2} = 2 x^{2} + 2

Move

2 x^{2}

to the left side

4 x^{2} = 2

Divide both sides by

4

x^{2} = \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{2} = \frac{1}{2}

- \frac{1}{2} = - \frac{1}{2}

x = \frac{1}{2}, x = - \frac{1}{2}

\frac{1}{8} - \frac{1}{4} \cdot \frac{3}{2} + \frac{3}{5}

2 y^{2} - 3 y - 20

(x - 4) (x - 4) = 0

9 x^{3} - 13 x + 4

3 x = 18

What are the solutions to the equation 3x(2x+3)=2x(x+4.5)+2 ?
The solutions to the equation 3x(2x+3)=2x(x+4.5)+2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))
Find the zeros of 3x(2x+3)=2x(x+4.5)+2
The zeros of 3x(2x+3)=2x(x+4.5)+2 are x= 1/(sqrt(2)),x=-1/(sqrt(2))