What is (y+1)/4-y/3 >1+(2y-1)/6 ?

The solution to (y+1)/4-y/3 >1+(2y-1)/6 is y<-7/5

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(y+1)/4-y/3 >1+(2y-1)/6

\frac{y + 1}{4} - \frac{y}{3} > 1 + \frac{2 y - 1}{6}

y < - \frac{7}{5}

Interval Notation

(- \infty, - \frac{7}{5})

Decimal Notation

y < - 1.4

Solution steps

\frac{y + 1}{4} - \frac{y}{3} > 1 + \frac{2 y - 1}{6}

Multiply by LCM

3 (y + 1) - 4 y > 12 + 2 (2 y - 1)

Expand

3 (y + 1) - 4 y : - y + 3

Expand

12 + 2 (2 y - 1) : 4 y + 10

- y + 3 > 4 y + 10

Move

3

to the right side

- y > 4 y + 7

Move

4 y

to the left side

- 5 y > 7

Multiply both sides by

- 1

5 y < - 7

Divide both sides by

5

y < - \frac{7}{5}

7 x - 3 = 32

\frac{( x + 10 ) ^{5}}{( x + 10 ) ^{4}}

\frac{x - 1}{x - 11} < 0

x^{2} + 4 x = 32

(4^{- 1})^{2}

What is (y+1)/4-y/3 >1+(2y-1)/6 ?
The solution to (y+1)/4-y/3 >1+(2y-1)/6 is y<-7/5