-16t^2+48t=0

解

- 16 t^{2} + 48 t = 0

t = 0, t = 3

解答ステップ

- 16 t^{2} + 48 t = 0

解くとthe二次式

t_{1, 2} = \frac{- 48 \pm 4 8 ^{2} - 4 ( - 16 ) \cdot 0}{2 ( - 16 )}

4 8^{2} - 4 (- 16) \cdot 0 = 48

t_{1, 2} = \frac{- 48 \pm 48}{2 ( - 16 )}

解を分離する

t_{1} = \frac{- 48 + 48}{2 ( - 16 )}, t_{2} = \frac{- 48 - 48}{2 ( - 16 )}

t = \frac{- 48 + 48}{2 ( - 16 )} : 0

t = \frac{- 48 - 48}{2 ( - 16 )} : 3

二次equationの解:

t = 0, t = 3