What is (x^2-xy)/(9y^2)*(3y)/(2x) ?

The solution to (x^2-xy)/(9y^2)*(3y)/(2x) is (x-y)/(6y)

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simplify (x^2-xy)/(9y^2)*(3y)/(2x)

simplify

\frac{x ^{2} - x y}{9 y ^{2}} \cdot \frac{3 y}{2 x}

\frac{x - y}{6 y}

Solution steps

\frac{x ^{2} - x y}{9 y ^{2}} \cdot \frac{3 y}{2 x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( x ^{2} - x y ) \cdot 3 y}{9 y ^{2} \cdot 2 x}

Factor the number:

9 = 3 \cdot 3

= \frac{( x ^{2} - x y ) \cdot 3 y}{3 \cdot 3 y ^{2} \cdot 2 x}

Cancel the common factor:

3

= \frac{( x ^{2} - x y ) y}{3 y ^{2} \cdot 2 x}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

y^{2} = yy

= \frac{( x ^{2} - x y ) y}{3 yy \cdot 2 x}

Cancel the common factor:

y

= \frac{x ^{2} - x y}{3 y \cdot 2 x}

Factor

x^{2} - x y : x (x - y)

= \frac{x ( x - y )}{3 y \cdot 2 x}

Cancel the common factor:

x

= \frac{x - y}{3 y \cdot 2}

Multiply the numbers:

3 \cdot 2 = 6

= \frac{x - y}{6 y}

x^{2} - 10 x + 24 \leq 0

\frac{4 p ^{6} q ^{- 2}}{24 p ^{6} q ^{9}}

3 π + \frac{π}{2}

2 + 3 x - 7 = 2 x + 5 + 3 x

6 x - 16 \geq 14

What is (x^2-xy)/(9y^2)*(3y)/(2x) ?
The solution to (x^2-xy)/(9y^2)*(3y)/(2x) is (x-y)/(6y)