What are the solutions to the equation 7x^2-x=6 ?

The solutions to the equation 7x^2-x=6 are x=1,x=-6/7

Find the zeros of 7x^2-x=6

The zeros of 7x^2-x=6 are x=1,x=-6/7

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7 x^{2} - x = 6

x = 1, x = - \frac{6}{7}

Decimal Notation

x = 1, x = - 0.85714 \dots

Solution steps

7 x^{2} - x = 6

Move

6

to the left side

7 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 7 ( - 6 )}{2 \cdot 7}

(- 1)^{2} - 4 \cdot 7 (- 6) = 13

x_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 7}, x_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 7}

x = \frac{- ( - 1 ) + 13}{2 \cdot 7} : 1

x = \frac{- ( - 1 ) - 13}{2 \cdot 7} : - \frac{6}{7}

The solutions to the quadratic equation are:

x = 1, x = - \frac{6}{7}

(x - 4)^{2} = 1

- 9 - 6

\frac{∣ x + 1 ∣}{∣ x - 2 ∣} < 1

x^{2} + x - 20 \geq 0

\frac{1 - 0.99}{0.99} \cdot 100

What are the solutions to the equation 7x^2-x=6 ?
The solutions to the equation 7x^2-x=6 are x=1,x=-6/7
Find the zeros of 7x^2-x=6
The zeros of 7x^2-x=6 are x=1,x=-6/7