What are the solutions to the equation 8c^2+11c+7=6c^2 ?

The solutions to the equation 8c^2+11c+7=6c^2 are c=(-11+sqrt(65))/4 ,c=(-11-sqrt(65))/4

Find the zeros of 8c^2+11c+7=6c^2

The zeros of 8c^2+11c+7=6c^2 are c=(-11+sqrt(65))/4 ,c=(-11-sqrt(65))/4

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8 c^{2} + 11 c + 7 = 6 c^{2}

c = \frac{- 11 + 65}{4}, c = \frac{- 11 - 65}{4}

Decimal Notation

c = - 0.73443 \dots, c = - 4.76556 \dots

Solution steps

8 c^{2} + 11 c + 7 = 6 c^{2}

Move

6 c^{2}

to the left side

2 c^{2} + 11 c + 7 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 \cdot 7 = 65

c_{1, 2} = \frac{- 11 \pm 65}{2 \cdot 2}

Separate the solutions

c_{1} = \frac{- 11 + 65}{2 \cdot 2}, c_{2} = \frac{- 11 - 65}{2 \cdot 2}

c = \frac{- 11 + 65}{2 \cdot 2} : \frac{- 11 + 65}{4}

c = \frac{- 11 - 65}{2 \cdot 2} : \frac{- 11 - 65}{4}

The solutions to the quadratic equation are:

c = \frac{- 11 + 65}{4}, c = \frac{- 11 - 65}{4}

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What are the solutions to the equation 8c^2+11c+7=6c^2 ?
The solutions to the equation 8c^2+11c+7=6c^2 are c=(-11+sqrt(65))/4 ,c=(-11-sqrt(65))/4
Find the zeros of 8c^2+11c+7=6c^2
The zeros of 8c^2+11c+7=6c^2 are c=(-11+sqrt(65))/4 ,c=(-11-sqrt(65))/4