What are the solutions to the equation x^2-2x-1=8 ?

The solutions to the equation x^2-2x-1=8 are x=1+sqrt(10),x=1-sqrt(10)

Find the zeros of x^2-2x-1=8

The zeros of x^2-2x-1=8 are x=1+sqrt(10),x=1-sqrt(10)

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x^{2} - 2 x - 1 = 8

x = 1 + 10, x = 1 - 10

Decimal Notation

x = 4.16227 \dots, x = - 2.16227 \dots

Solution steps

x^{2} - 2 x - 1 = 8

Move

8

to the left side

x^{2} - 2 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 9) = 210

x_{1, 2} = \frac{- ( - 2 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 10}{2 \cdot 1} : 1 + 10

x = \frac{- ( - 2 ) - 2 10}{2 \cdot 1} : 1 - 10

The solutions to the quadratic equation are:

x = 1 + 10, x = 1 - 10

- 16 t^{2} + 32 t + 240 = 0

3 (2 x - 7) = 6 (x - 4) - 3

\frac{6 - ( - 7 )}{- 3 - ( - 7 )}

28 a + 14

g (- 2) = 2 (- 2) + 1

What are the solutions to the equation x^2-2x-1=8 ?
The solutions to the equation x^2-2x-1=8 are x=1+sqrt(10),x=1-sqrt(10)
Find the zeros of x^2-2x-1=8
The zeros of x^2-2x-1=8 are x=1+sqrt(10),x=1-sqrt(10)