What are the solutions to the equation (2/7)c^2-(1/2)c-(3/14)=0 ?

The solutions to the equation (2/7)c^2-(1/2)c-(3/14)=0 are c=(7+sqrt(97))/8 ,c=(7-sqrt(97))/8

Find the zeros of (2/7)c^2-(1/2)c-(3/14)=0

The zeros of (2/7)c^2-(1/2)c-(3/14)=0 are c=(7+sqrt(97))/8 ,c=(7-sqrt(97))/8

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(\frac{2}{7}) c^{2} - (\frac{1}{2}) c - (\frac{3}{14}) = 0

c = \frac{7 + 97}{8}, c = \frac{7 - 97}{8}

Decimal Notation

c = 2.10610 \dots, c = - 0.35610 \dots

Solution steps

(\frac{2}{7}) c^{2} - (\frac{1}{2}) c - (\frac{3}{14}) = 0

Refine

\frac{2}{7} c^{2} - \frac{1}{2} c - \frac{3}{14} = 0

Write in the standard form

a x^{2} + b x + c = 0

\frac{2 c ^{2}}{7} - \frac{c}{2} - \frac{3}{14} = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - \frac{1}{2} ) \pm ( - \frac{1}{2} ) ^{2} - 4 \cdot \frac{2}{7} ( - \frac{3}{14} )}{2 \cdot \frac{2}{7}}

(- \frac{1}{2})^{2} - 4 \cdot \frac{2}{7} (- \frac{3}{14}) = \frac{97}{14}

c_{1, 2} = \frac{- ( - \frac{1}{2} ) \pm \frac{97}{14}}{2 \cdot \frac{2}{7}}

Separate the solutions

c_{1} = \frac{- ( - \frac{1}{2} ) + \frac{97}{14}}{2 \cdot \frac{2}{7}}, c_{2} = \frac{- ( - \frac{1}{2} ) - \frac{97}{14}}{2 \cdot \frac{2}{7}}

c = \frac{- ( - \frac{1}{2} ) + \frac{97}{14}}{2 \frac{2}{7}} : \frac{7 + 97}{8}

c = \frac{- ( - \frac{1}{2} ) - \frac{97}{14}}{2 \frac{2}{7}} : \frac{7 - 97}{8}

The solutions to the quadratic equation are:

c = \frac{7 + 97}{8}, c = \frac{7 - 97}{8}

n^{2} - 5 n = 24

3 a^{4} - a^{2} - 24

\frac{- 11 + n}{15} < - 1

∣ 2 v + 11 ∣ = 3

\frac{9 x}{4} - 6 = \frac{2 x}{3} + \frac{1}{3}

What are the solutions to the equation (2/7)c^2-(1/2)c-(3/14)=0 ?
The solutions to the equation (2/7)c^2-(1/2)c-(3/14)=0 are c=(7+sqrt(97))/8 ,c=(7-sqrt(97))/8
Find the zeros of (2/7)c^2-(1/2)c-(3/14)=0
The zeros of (2/7)c^2-(1/2)c-(3/14)=0 are c=(7+sqrt(97))/8 ,c=(7-sqrt(97))/8