What are the solutions to the equation s^2+23s+22=0 ?

The solutions to the equation s^2+23s+22=0 are s=-1,s=-22

Find the zeros of s^2+23s+22=0

The zeros of s^2+23s+22=0 are s=-1,s=-22

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s^{2} + 23 s + 22 = 0

s = - 1, s = - 22

Solution steps

s^{2} + 23 s + 22 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 23 \pm 2 3 ^{2} - 4 \cdot 1 \cdot 22}{2 \cdot 1}

2 3^{2} - 4 \cdot 1 \cdot 22 = 21

s_{1, 2} = \frac{- 23 \pm 21}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 23 + 21}{2 \cdot 1}, s_{2} = \frac{- 23 - 21}{2 \cdot 1}

s = \frac{- 23 + 21}{2 \cdot 1} : - 1

s = \frac{- 23 - 21}{2 \cdot 1} : - 22

The solutions to the quadratic equation are:

s = - 1, s = - 22

8 x^{2} + 30 x - 27

(x + 2)^{2} (x - 4)^{3} (5 - 2 x) < 0

\frac{2 2}{4}

128 - 3 \cdot (x + 4) = 23

(2 x - 1)^{2} = 16

What are the solutions to the equation s^2+23s+22=0 ?
The solutions to the equation s^2+23s+22=0 are s=-1,s=-22
Find the zeros of s^2+23s+22=0
The zeros of s^2+23s+22=0 are s=-1,s=-22