What are the solutions to the equation r^2+2r-1=0 ?

The solutions to the equation r^2+2r-1=0 are r=-1+sqrt(2),r=-1-sqrt(2)

Find the zeros of r^2+2r-1=0

The zeros of r^2+2r-1=0 are r=-1+sqrt(2),r=-1-sqrt(2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

r^{2} + 2 r - 1 = 0

r = - 1 + 2, r = - 1 - 2

Decimal Notation

r = 0.41421 \dots, r = - 2.41421 \dots

Solution steps

r^{2} + 2 r - 1 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 1) = 22

r_{1, 2} = \frac{- 2 \pm 2 2}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 2 + 2 2}{2 \cdot 1}, r_{2} = \frac{- 2 - 2 2}{2 \cdot 1}

r = \frac{- 2 + 2 2}{2 \cdot 1} : - 1 + 2

r = \frac{- 2 - 2 2}{2 \cdot 1} : - 1 - 2

The solutions to the quadratic equation are:

r = - 1 + 2, r = - 1 - 2

\frac{1}{4} \cdot \frac{1}{2}

x^{2} + 7 x + 12 > 0

- \frac{3}{4} x = - \frac{3}{4}

- 9 x = - 36

What are the solutions to the equation r^2+2r-1=0 ?
The solutions to the equation r^2+2r-1=0 are r=-1+sqrt(2),r=-1-sqrt(2)
Find the zeros of r^2+2r-1=0
The zeros of r^2+2r-1=0 are r=-1+sqrt(2),r=-1-sqrt(2)