What are the solutions to the equation x^2-11=4x ?

The solutions to the equation x^2-11=4x are x=2+sqrt(15),x=2-sqrt(15)

Find the zeros of x^2-11=4x

The zeros of x^2-11=4x are x=2+sqrt(15),x=2-sqrt(15)

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x^{2} - 11 = 4 x

x = 2 + 15, x = 2 - 15

Decimal Notation

x = 5.87298 \dots, x = - 1.87298 \dots

Solution steps

x^{2} - 11 = 4 x

Move

4 x

to the left side

x^{2} - 11 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 4 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 4)^{2} - 4 \cdot 1 \cdot (- 11) = 215

x_{1, 2} = \frac{- ( - 4 ) \pm 2 15}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 15}{2 \cdot 1}, x_{2} = \frac{- ( - 4 ) - 2 15}{2 \cdot 1}

x = \frac{- ( - 4 ) + 2 15}{2 \cdot 1} : 2 + 15

x = \frac{- ( - 4 ) - 2 15}{2 \cdot 1} : 2 - 15

The solutions to the quadratic equation are:

x = 2 + 15, x = 2 - 15

2 + ∣ 5 t - 2 ∣ = 5

4^{- 4}

(3 x - 2 y)^{3} - (5 y + 3 x)^{3}

3 w - 3 - (2 w + 2) = 8

2 x^{2} = 9 x + 56

What are the solutions to the equation x^2-11=4x ?
The solutions to the equation x^2-11=4x are x=2+sqrt(15),x=2-sqrt(15)
Find the zeros of x^2-11=4x
The zeros of x^2-11=4x are x=2+sqrt(15),x=2-sqrt(15)