What are the solutions to the equation 5a^2-11a=12 ?

The solutions to the equation 5a^2-11a=12 are a=3,a=-4/5

Find the zeros of 5a^2-11a=12

The zeros of 5a^2-11a=12 are a=3,a=-4/5

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5 a^{2} - 11 a = 12

a = 3, a = - \frac{4}{5}

Decimal Notation

a = 3, a = - 0.8

Solution steps

5 a^{2} - 11 a = 12

Move

12

to the left side

5 a^{2} - 11 a - 12 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 5 ( - 12 )}{2 \cdot 5}

(- 11)^{2} - 4 \cdot 5 (- 12) = 19

a_{1, 2} = \frac{- ( - 11 ) \pm 19}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 11 ) + 19}{2 \cdot 5}, a_{2} = \frac{- ( - 11 ) - 19}{2 \cdot 5}

a = \frac{- ( - 11 ) + 19}{2 \cdot 5} : 3

a = \frac{- ( - 11 ) - 19}{2 \cdot 5} : - \frac{4}{5}

The solutions to the quadratic equation are:

a = 3, a = - \frac{4}{5}

3 x - 7 \geq 14

12 + w < 19

\frac{5}{9} (9 d - 27) - 14 = 6

\frac{x}{- 2} > 4

\frac{1}{2} t^{2} - 36 = 0

What are the solutions to the equation 5a^2-11a=12 ?
The solutions to the equation 5a^2-11a=12 are a=3,a=-4/5
Find the zeros of 5a^2-11a=12
The zeros of 5a^2-11a=12 are a=3,a=-4/5