faktorisieren 1/4-9a^2

Lösung

faktorisieren

\frac{1}{4} - 9 a^{2}

(\frac{1}{2} + 3 a) (\frac{1}{2} - 3 a)

Schritte zur Lösung

\frac{1}{4} - 9 a^{2}

\frac{1}{4} = (\frac{1}{2})^{2}

9 a^{2} = (3 a)^{2}

= (\frac{1}{2})^{2} - (3 a)^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(\frac{1}{2})^{2} - (3 a)^{2} = (\frac{1}{2} + 3 a) (\frac{1}{2} - 3 a)

= (\frac{1}{2} + 3 a) (\frac{1}{2} - 3 a)

s im pl i f y 3 x^{3} - x^{3}

\frac{47}{9}

e x p an d 2 x (5 x - 2)

\frac{23}{20}

7 \div \frac{1}{2}