What are the solutions to the equation 2(x-1)^2+7=39 ?

The solutions to the equation 2(x-1)^2+7=39 are x=5,x=-3

Find the zeros of 2(x-1)^2+7=39

The zeros of 2(x-1)^2+7=39 are x=5,x=-3

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2 (x - 1)^{2} + 7 = 39

x = 5, x = - 3

Solution steps

2 (x - 1)^{2} + 7 = 39

Move

7

to the right side

2 (x - 1)^{2} = 32

Divide both sides by

2

(x - 1)^{2} = 16

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 16 : x = 5

Solve

x - 1 = - 16 : x = - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

(x - 7)^{2} + 4 = 0

- 4 x - 32 < 4

∣ x - 2 ∣ < 7

x^{2} + 6 x + 5 = 0

What are the solutions to the equation 2(x-1)^2+7=39 ?
The solutions to the equation 2(x-1)^2+7=39 are x=5,x=-3
Find the zeros of 2(x-1)^2+7=39
The zeros of 2(x-1)^2+7=39 are x=5,x=-3