What are the solutions to the equation x^2-11x+14=0 ?

The solutions to the equation x^2-11x+14=0 are x=(11+sqrt(65))/2 ,x=(11-sqrt(65))/2

Find the zeros of x^2-11x+14=0

The zeros of x^2-11x+14=0 are x=(11+sqrt(65))/2 ,x=(11-sqrt(65))/2

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x^{2} - 11 x + 14 = 0

x = \frac{11 + 65}{2}, x = \frac{11 - 65}{2}

Decimal Notation

x = 9.53112 \dots, x = 1.46887 \dots

Solution steps

x^{2} - 11 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 1 \cdot 14}{2 \cdot 1}

(- 11)^{2} - 4 \cdot 1 \cdot 14 = 65

x_{1, 2} = \frac{- ( - 11 ) \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 11 ) + 65}{2 \cdot 1}, x_{2} = \frac{- ( - 11 ) - 65}{2 \cdot 1}

x = \frac{- ( - 11 ) + 65}{2 \cdot 1} : \frac{11 + 65}{2}

x = \frac{- ( - 11 ) - 65}{2 \cdot 1} : \frac{11 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{11 + 65}{2}, x = \frac{11 - 65}{2}

(\frac{a ^{5} b ^{- 13}}{2 a ^{- 5} b ^{- 8}})^{- 2}

- 6 (3 x + 9) = - 270

x^{2} + 5 x - 24

x^{2} - 9 x - 2 = 0

(7 - 2 i)^{2}

What are the solutions to the equation x^2-11x+14=0 ?
The solutions to the equation x^2-11x+14=0 are x=(11+sqrt(65))/2 ,x=(11-sqrt(65))/2
Find the zeros of x^2-11x+14=0
The zeros of x^2-11x+14=0 are x=(11+sqrt(65))/2 ,x=(11-sqrt(65))/2