What are the solutions to the equation x^2-7x+2=0 ?

The solutions to the equation x^2-7x+2=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2

Find the zeros of x^2-7x+2=0

The zeros of x^2-7x+2=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2

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x^{2} - 7 x + 2 = 0

x = \frac{7 + 41}{2}, x = \frac{7 - 41}{2}

Decimal Notation

x = 6.70156 \dots, x = 0.29843 \dots

Solution steps

x^{2} - 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 2 = 41

x_{1, 2} = \frac{- ( - 7 ) \pm 41}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 41}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 41}{2 \cdot 1}

x = \frac{- ( - 7 ) + 41}{2 \cdot 1} : \frac{7 + 41}{2}

x = \frac{- ( - 7 ) - 41}{2 \cdot 1} : \frac{7 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 41}{2}, x = \frac{7 - 41}{2}

3 (2 x + 1) + 6 = 2 (x + 2)

9 t = 2 t^{2}

x - 7 = 2

4.9 \geq h - 5

- \frac{x}{4} = \frac{2 x}{3}

What are the solutions to the equation x^2-7x+2=0 ?
The solutions to the equation x^2-7x+2=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2
Find the zeros of x^2-7x+2=0
The zeros of x^2-7x+2=0 are x=(7+sqrt(41))/2 ,x=(7-sqrt(41))/2