What is |x|+|x-2|>2 ?

The solution to |x|+|x-2|>2 is x 2

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|x|+|x-2|>2

∣ x ∣ + ∣ x - 2 ∣ > 2

x < 0 or x > 2

Interval Notation

(- \infty, 0) \cup (2, \infty)

Solution steps

∣ x ∣ + ∣ x - 2 ∣ > 2

Find positive and negative intervals

x < 0, 0 \leq x < 2, x \geq 2

Solve the inequality for each interval

x < 0 or No Solution or x > 2

Merge Overlapping Intervals

x < 0 or x > 2

- 5 (\frac{1}{2})^{2}

- 56 k = - 10

\frac{8}{14} = \frac{x}{12}

2 x^{2} + 5 x - 7

\frac{1}{4 ^{5}}