What are the solutions to the equation 2x^2+25x+33=0 ?

The solutions to the equation 2x^2+25x+33=0 are x=-3/2 ,x=-11

Find the zeros of 2x^2+25x+33=0

The zeros of 2x^2+25x+33=0 are x=-3/2 ,x=-11

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2 x^{2} + 25 x + 33 = 0

x = - \frac{3}{2}, x = - 11

Decimal Notation

x = - 1.5, x = - 11

Solution steps

2 x^{2} + 25 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 2 \cdot 33}{2 \cdot 2}

2 5^{2} - 4 \cdot 2 \cdot 33 = 19

x_{1, 2} = \frac{- 25 \pm 19}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 25 + 19}{2 \cdot 2}, x_{2} = \frac{- 25 - 19}{2 \cdot 2}

x = \frac{- 25 + 19}{2 \cdot 2} : - \frac{3}{2}

x = \frac{- 25 - 19}{2 \cdot 2} : - 11

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = - 11

3 t + 4 = 12 + 3 t

5 - 3125

- 4 x - 12

- 6 + 7

\frac{5}{3}

What are the solutions to the equation 2x^2+25x+33=0 ?
The solutions to the equation 2x^2+25x+33=0 are x=-3/2 ,x=-11
Find the zeros of 2x^2+25x+33=0
The zeros of 2x^2+25x+33=0 are x=-3/2 ,x=-11