What are the solutions to the equation w^2+7w+10=0 ?

The solutions to the equation w^2+7w+10=0 are w=-2,w=-5

Find the zeros of w^2+7w+10=0

The zeros of w^2+7w+10=0 are w=-2,w=-5

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w^{2} + 7 w + 10 = 0

w = - 2, w = - 5

Solution steps

w^{2} + 7 w + 10 = 0

Solve with the quadratic formula

w_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

7^{2} - 4 \cdot 1 \cdot 10 = 3

w_{1, 2} = \frac{- 7 \pm 3}{2 \cdot 1}

Separate the solutions

w_{1} = \frac{- 7 + 3}{2 \cdot 1}, w_{2} = \frac{- 7 - 3}{2 \cdot 1}

w = \frac{- 7 + 3}{2 \cdot 1} : - 2

w = \frac{- 7 - 3}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

w = - 2, w = - 5

\frac{3}{5} x + 2 - \frac{1}{2} = 4

2 x^{2} - x = 3

\frac{n}{24} = - 2

2^{9} - 1

\frac{32}{9}

What are the solutions to the equation w^2+7w+10=0 ?
The solutions to the equation w^2+7w+10=0 are w=-2,w=-5
Find the zeros of w^2+7w+10=0
The zeros of w^2+7w+10=0 are w=-2,w=-5