What are the solutions to the equation y^2-8y-5=0 ?

The solutions to the equation y^2-8y-5=0 are y=4+sqrt(21),y=4-sqrt(21)

Find the zeros of y^2-8y-5=0

The zeros of y^2-8y-5=0 are y=4+sqrt(21),y=4-sqrt(21)

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y^{2} - 8 y - 5 = 0

y = 4 + 21, y = 4 - 21

Decimal Notation

y = 8.58257 \dots, y = - 0.58257 \dots

Solution steps

y^{2} - 8 y - 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 5) = 221

y_{1, 2} = \frac{- ( - 8 ) \pm 2 21}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 8 ) + 2 21}{2 \cdot 1}, y_{2} = \frac{- ( - 8 ) - 2 21}{2 \cdot 1}

y = \frac{- ( - 8 ) + 2 21}{2 \cdot 1} : 4 + 21

y = \frac{- ( - 8 ) - 2 21}{2 \cdot 1} : 4 - 21

The solutions to the quadratic equation are:

y = 4 + 21, y = 4 - 21

\frac{4}{3} y + 2 = 4 y - 4

- λ^{3} + 3 λ + 2

19 \leq 5 - 4 x

2 a^{2} + 14 a

\frac{8}{\frac{1}{2}}

What are the solutions to the equation y^2-8y-5=0 ?
The solutions to the equation y^2-8y-5=0 are y=4+sqrt(21),y=4-sqrt(21)
Find the zeros of y^2-8y-5=0
The zeros of y^2-8y-5=0 are y=4+sqrt(21),y=4-sqrt(21)